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Post by tonyqj on Oct 31, 2016 18:13:48 GMT
Gibbo v Nick, so glad I joined this site, sits back to enjoy the show..... Where's Β Chris W when you need him ? π Oh God no, please. Not broken maths as well!
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Post by Graham on Oct 31, 2016 18:31:18 GMT
Draw me a circuit which will pass a total of x (pick your own non zero value) amp hours using no energy. Any circuit where the resistance is zero, such as a superconducting ring. Nick, stop playing with words either use the language that we all use about batteries with the meanings that it we use, because it is us you are talking to not some esoteric lot. I think you have gone way of course and Gibbo has caught you out with a simple question. Talk in real terms and produce a circuit. Thank you BTW my brain was right you were wrong in real life language.
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Post by Telemachus on Oct 31, 2016 18:37:27 GMT
Any circuit where the resistance is zero, such as a superconducting ring. Nick, stop playing with words either use the language that we all use about batteries with the meanings that it we use, because it is us you are talking to no some esoteric lot. I think you have gone way of course and Gibbo has caught you out with a simple question. Talk in real terms and produce a circuit. Thank you BTW my brain was right you were wrong in real life language. If the circuit has resistance, there will be voltage drop. Thus in order to keep the charge moving you have to have a voltage source to "pump" it and thus if a circuit has resistance, power is needed to move the charge. But note MOVE the charge. If the charge is not moving, there is no power required. It was a simple question (to which I provided a correct if somewhat esoteric answer) but the point is that it is a question to make a point that we all agree on (hopefully) - i.e. the veracity of power = amps times volts (or coulombs per second times volts). You haven't argued with Gibbo before, when he is losing an argument he tends to change the question!
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Post by Deleted on Oct 31, 2016 18:47:15 GMT
Gibbo v Nick, so glad I joined this site, sits back to enjoy the show..... Where's Chris W when you need him ? π Before my time, but I have read some of the posts on the other site. Gibbo is a legend over there. Perhaps he has found his match in Nick. Stay tuned folks.
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Post by Graham on Oct 31, 2016 18:52:39 GMT
Nick, stop playing with words either use the language that we all use about batteries with the meanings that it we use, because it is us you are talking to no some esoteric lot. I think you have gone way of course and Gibbo has caught you out with a simple question. Talk in real terms and produce a circuit. Thank you BTW my brain was right you were wrong in real life language. If the circuit has resistance, there will be voltage drop. Thus in order to keep the charge moving you have to have a voltage source to "pump" it and thus if a circuit has resistance, power is needed to move the charge. But note MOVE the charge. If the charge is not moving, there is no power required. It was a simple question (to which I provided a correct if somewhat esoteric answer) but the point is that it is a question to make a point that we all agree on (hopefully) - i.e. the veracity of power = amps times volts (or coulombs per second times volts). You haven't argued with Gibbo before, when he is losing an argument he tends to change the question! That is where you go so wrong, you twist words you fail to respect those you are speaking to. When I say a circuit I mean one that meets the ability for me to go and build in my garage now. Not one that would cost more than I got for Clarence. A battery in real life is charged down cable made of copper at room temperature thus has resistance. I would suggest you come up with some real life answers that work in real everyday life on a boat on a canal without esoteric additions. Be real young man. Oh btw you were arguing with me earlier I don't change my questions
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Post by Telemachus on Oct 31, 2016 18:56:58 GMT
If the circuit has resistance, there will be voltage drop. Thus in order to keep the charge moving you have to have a voltage source to "pump" it and thus if a circuit has resistance, power is needed to move the charge. But note MOVE the charge. If the charge is not moving, there is no power required. It was a simple question (to which I provided a correct if somewhat esoteric answer) but the point is that it is a question to make a point that we all agree on (hopefully) - i.e. the veracity of power = amps times volts (or coulombs per second times volts). You haven't argued with Gibbo before, when he is losing an argument he tends to change the question! That is where you go so wrong, you twist words you fail to respect those you are speaking to. When I say a circuit I mean one that meets the ability for me to go and build in my garage now. Not one that would cost more than I got for Clarence. A battery in real life is charged down cable made of copper at room temperature thus has resistance. I would suggest you come up with some real life answers that work in real everyday life on a boat on a canal without esoteric additions. Be real young man. I'm slightly losing track of the ever changing questions but if you want to build a circuit with resistance, it will dissipate power and thus need a source of power to keep the current flowing. Surely every one knows that? However the power is as a result of volt drop, not as a result of "current drop" which of course doesn't exist as a concept. Review Kirchhoff's law if in doubt. So I'm not quite sure what the significance of the question is since the answer is blatantly obvious.
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Post by Graham on Oct 31, 2016 19:10:19 GMT
That is where you go so wrong, you twist words you fail to respect those you are speaking to. When I say a circuit I mean one that meets the ability for me to go and build in my garage now. Not one that would cost more than I got for Clarence. A battery in real life is charged down cable made of copper at room temperature thus has resistance. I would suggest you come up with some real life answers that work in real everyday life on a boat on a canal without esoteric additions. Be real young man. I'm slightly losing track of the ever changing questions but if you want to build a circuit with resistance, it will dissipate power and thus need a source of power to keep the current flowing. Surely every one knows that? However the power is as a result of volt drop, not as a result of "current drop" which of course doesn't exist as a concept. Review Kirchhoff's law if in doubt. So I'm not quite sure what the significance of the question is since the answer is blatantly obvious. Why don't you give Gibbo a real life circuit and see where it goes. You think the answer is blatant I don't but you must get into the real world and not insult us and twist words from the meanings we give them in our rel world of boats and trying to keep batteries charged and able to supply the power, note that word power, energy note that word we need to run our boats.
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Post by Telemachus on Oct 31, 2016 19:15:25 GMT
I'm slightly losing track of the ever changing questions but if you want to build a circuit with resistance, it will dissipate power and thus need a source of power to keep the current flowing. Surely every one knows that? However the power is as a result of volt drop, not as a result of "current drop" which of course doesn't exist as a concept. Review Kirchhoff's law if in doubt. So I'm not quite sure what the significance of the question is since the answer is blatantly obvious. Why don't you give Gibbo a real life circuit and see where it goes. You think the answer is blatant I don't but you must get into the real world and not insult us and twist words from the meanings we give them in our rel world of boats and trying to keep batteries charged and able to supply the power, note that word power, energy note that word we need to run our boats. I've slightly lost track of how all this started but I think it was about CEF. I'll say it again, CEF is not about power it is about charge (or coulombic) efficiency. So power lost through heating etc cannot be a facet of CEF. Needless to say I agree that power and energy are required to charge the batteries - surely that was never in doubt? If you have a specific question or point of debate please express it. But if you want to propose something that defies the basic laws of physics, I will argue. Surely you would expect me to?
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Post by Graham on Oct 31, 2016 19:26:20 GMT
Why don't you give Gibbo a real life circuit and see where it goes. You think the answer is blatant I don't but you must get into the real world and not insult us and twist words from the meanings we give them in our rel world of boats and trying to keep batteries charged and able to supply the power, note that word power, energy note that word we need to run our boats. I've slightly lost track of how all this started but I think it was about CEF. I'll say it again, CEF is not about power it is about charge (or coulombic) efficiency. So power lost through heating etc cannot be a facet of CEF. Needless to say I agree that power and energy are required to charge the batteries - surely that was never in doubt? If you have a specific question or point of debate please express it. But if you want to propose something that defies the basic laws of physics, I will argue. Surely you would expect me to? Answer Gibbo's question in detail bases on real life and something I can setup in my garage I am out of here until Gibbo has and answer and Gibbo has reviewed
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Post by Telemachus on Oct 31, 2016 19:29:03 GMT
What was the question?
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Post by JohnV on Oct 31, 2016 19:31:47 GMT
The meaning of life the universe and everything !!!
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Post by Telemachus on Oct 31, 2016 19:37:26 GMT
In that case, the answer is easy.
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Post by Graham on Oct 31, 2016 19:38:35 GMT
Just a real life circuit that operates as you described earlier before Gibbo left us. Can't remember the exact words you you used about charge etc
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Post by Graham on Oct 31, 2016 19:40:17 GMT
The meaning of life the universe and everything !!! 42
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Post by Telemachus on Oct 31, 2016 19:41:07 GMT
Just a real life circuit that operates as you described earlier before Gibbo left us. Can't remember the exact words you you used about charge etc I didn't describe any circuit, well apart from the superconducting one.
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